Carbonation in Lambic: Difference between revisions

← Older edit Newer edit →

@@ Line 125: / Line 125: @@
 [H<sup>+</sup>] = 10<sup>-pH</sup>
-[CO<sub>2</sub> (aq)] = 4.3 * V<sub>CO<sub>2</sub>
+[CO<sub>2</sub> (aq)] = 4.3 * V<sub>CO<sub>2</sub></sub>
-[H<sub>2</sub>CO<sub>3</sub>] = Ka<sub>0</sub> * 4.3 * V<sub>CO<sub>2</sub>
+[H<sub>2</sub>CO<sub>3</sub>] = Ka<sub>0</sub> * 4.3 * V<sub>CO<sub>2</sub></sub>
-[HCO<sub>3</sub><sup>-</sup>] = Ka<sub>0</sub> * Ka<sub>1</sub> * 4.3 * V<sub>CO<sub>2</sub> * 10<sup>pH</sup>
+[HCO<sub>3</sub><sup>-</sup>] = Ka<sub>0</sub> * Ka<sub>1</sub> * 4.3 * V<sub>CO<sub>2</sub></sub> * 10<sup>pH</sup>
-[CO<sub>3</sub><sup>2-</sup>] = Ka<sub>0</sub> * Ka<sub>1</sub> * Ka<sub>2</sub> * 4.3 * V<sub>CO<sub>2</sub> * 10<sup>2pH</sup>
+[CO<sub>3</sub><sup>2-</sup>] = Ka<sub>0</sub> * Ka<sub>1</sub> * Ka<sub>2</sub> * 4.3 * V<sub>CO<sub>2</sub></sub> * 10<sup>2pH</sup>
-OLDMATH
-[CO<sub>2</sub> (aq)] = (4.3*10<sup>-2(pH + 1)</sup>)V<sub>CO<sub>2</sub></sub>/((1+Ka<sub>0</sub>)*10<sup>-2pH</sup> + Ka<sub>0</sub> * Ka<sub>1</sub> * 10<sup>-pH</sup> + Ka<sub>0</sub> * Ka<sub>1</sub> * Ka<sub>2</sub>)
-[H<sub>2</sub>CO<sub>3</sub>] = Ka<sub>0</sub> * [CO<sub>2</sub> (aq)]
-[HCO<sub>3</sub><sup>-</sup>] = Ka<sub>1</sub> * [H<sub>2</sub>CO<sub>3</sub>] * 10<sup>-pH</sup>
-[CO<sub>3</sub><sup>2-</sup>] = Ka<sub>2</sub> * [HCO<sub>3</sub><sup>-</sup>] * 10<sup>-pH</sup>
 Where