Carbonation in Lambic: Difference between revisions
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Note that the denominator is the total concentration of CO<sub>2</sub> and products to an approximation better than one part in two million. Combining this with the total carbon from above and re-arranging, we can write | Note that the denominator is the total concentration of CO<sub>2</sub> and products to an approximation better than one part in two million. Combining this with the total carbon from above and re-arranging, we can write | ||
[CO<sub>2</sub> (aq)] = (4.3*10<sup>-2(pH + 1)</sup>)V<sub>CO<sub>2</sub></sub>/((1+Ka<sub>0</sub>)*10<sup>-2pH</sup> + Ka<sub>0</sub> * Ka<sub>1</sub> * 10<sup>-pH</sup> + Ka<sub>0</sub> * Ka<sub>1</ | [CO<sub>2</sub> (aq)] = (4.3*10<sup>-2(pH + 1)</sup>)V<sub>CO<sub>2</sub></sub>/((1+Ka<sub>0</sub>)*10<sup>-2pH</sup> + Ka<sub>0</sub> * Ka<sub>1</sub> * 10<sup>-pH</sup> + Ka<sub>0</sub> * Ka<sub>1</sub> * Ka<sub>2</sub>) | ||
[H<sub>2</sub>CO<sub>3</sub>] = Ka<sub>0</sub> * [CO<sub>2</sub> (aq)] | [H<sub>2</sub>CO<sub>3</sub>] = Ka<sub>0</sub> * [CO<sub>2</sub> (aq)] | ||
[HCO<sub>3</sub><sup>-</sup>] = Ka<sub>1</sub> * [H<sub>2</sub>CO<sub>3</sub>] * 10<sup>-pH</sup> | [HCO<sub>3</sub><sup>-</sup>] = Ka<sub>1</sub> * [H<sub>2</sub>CO<sub>3</sub>] * 10<sup>-pH</sup> | ||